Помогите решить: [latex] \frac{4}{x-1} - \frac{4}{x+1} =1[/latex]

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[latex] \frac{4}{x-1} - \frac{4}{x+1} =1 \\ \frac{4}{x-1} - \frac{4}{x+1} -1=0 \\ \frac{4(x+1)-4(x-1)-(x-1)(x+1)}{(x-1)(x+1)} =0 \\ \frac{4x+4-4x+4- x^{2} +1}{(x+1)(x-1)} = \frac{- x^{2} +9}{(x+1)(x-1)} = \frac{- x^{2} +9}{ x^{2} -1} \\ x \neq +-1 \\ - x^{2} +9=0 \\ x^{2} =9 \\ x=+-3[/latex]