Ответ(ы) на вопрос:
Гость(a-1)/(a+2) - (1-a)/(a^2+3a+2)
a^2+3a+2 = (a +1 )(a +2 )
D = 9 - 8 = 1
a1 = (-3 + 1)/2 = -2/2 = -1
a2 = (-3 - 1)/2 = -4/2 = -2
(a-1)/(a+2) - (1-a)/(a+2)(a + 1) = (a^2 - 1 - 1 + a)/(a + 2)(a + 1) = (a^2 + a - 2)/(a + 2)(a + 1)a^2 + a - 2 = (a - 1)(a + 2)D = 1 + 8 = 3
a1 = (-1 + 3)/2 = 2/2 = 1
a2 = (-2 - 3)/2 = -4/2 = -2
(a - 1)(a + 2)/(a + 2)(a + 1) = (a - 1)/(a + 1)
Не нашли ответ?
Похожие вопросы