Log^x+1(x-1/2) = log^x-1/2 (x+1)

условимся : рядом логарифмом пишу основание потом число log(x+1) (x-1/2)=1/log(x+1) (x-1/2) log(x+1) (x-1/2)-1/log(x+1) (x-1/2)=0 (log(x+1) (x-1/2)-1=0. log(x+1) (x-1/2)0 (log(x+1) (x-1/2)-1)*(log(x+1) (x-1/2)+1)=0. x>1/2. x3/2 log(x+1) (x-1/2)-1=0 или log(x+1) (x-1/2)+1=0 log(x+1) (x-1/2)=1 log(x+1) (x-1/2)=-1 x+1=x-1/2 x-1/2=1/(x+1) нет решения (x-1/2)(x+1)-1=0 x-1/2x+x-1/2-1=0 x+1/2x-3/2=0 /*2 2x+x-3=0 D=1-4*2*-3=25 x1=-1+5)/4=4/4=1 x2=-1-5)/4=-6/4=-3/2 -3/2-постороний корень ответ 1