1-sinx=sinx 2cos2x=2. 5-5sinx=cos2x

1) 1 - sin x = Sin x 2Sin x = 1 Sin x = 1/2 x = (-1)^n arcSin 1/2 + nπ, n∈Z x = (-1)^n π/6 + nπ,n∈Z 2) 2 Cos x = 2 Cos x = 1 x = 2πk , k∈Z 3) 5 - 5 Sin x = Cos2x     5 - 5Sin x = 1 - 2Sin² x     2 Sin² x -5Sin x +4 = 0 Sin x = t 2t² - 5t +4 = 0 D = 1 t1= 3/2 t2 = 1 a) Sin x = 3/2 нет решений б) Sin x = 1      x = π/2 + 2πk , k∈Z