(1/9)^x/5 больше 3 Пожалуйста решите

[latex] (\frac{1}{9})^{ \frac{x}{5}}\ \textgreater \ 3\\\\(3^{-2})^{ \frac{x}{5}}\ \textgreater \ 3\\\\3^{- \frac{x}{5}}\ \textgreater \ 3^{1} \; \; \; \; \; 3\ \textgreater \ 1\\\\- \frac{x}{5}\ \textgreater \ 1\\\\ \frac{x}{5}\ \textless \ -1\\\\x\ \textless \ -5\\\\x\in(-\infty;-5) [/latex]