-4 целых6/35 -(-3 целых9/28)=?

[latex]-4 \frac{6}{35} -(-3 \frac{9}{28} )=-4 \frac{6}{35} +3 \frac{9}{28} = -\frac{146}{35} + \frac{93}{28} = \frac{-584+465}{140} =- \frac{119}{140} =- \frac{17}{20} [/latex]