8х²-10х+2=0 решите пжлст

[latex]8 x^{2} -10x+2=0[/latex] [latex]D = b^{2} -4ac=100-4*8*2=100-64=36[/latex] [latex] x_{1} = \frac{-b+ \sqrt{D} }{2a} = \frac{10+ \sqrt{36} }{2*8} = \frac{10+6}{16} = \frac{16}{16} =1[/latex] [latex] x_{2} = \frac{-b- \sqrt{D} }{2a} = \frac{10- \sqrt{36} }{2*8} = \frac{10-6}{16} = \frac{4}{16} = \frac{1}{4} [/latex] Ответ: [latex] x_{1} =1; x_{2} = \frac{1}{4} [/latex]