C 2, срочно заранее спасибо

[latex] \left \{ {{log_{\sqrt{3}}(y-x) = 2} \atop {3^x*4^y = 768}} \right. \\ log_3(y-x) = 1 \\ \left \{ {{y-x=3 =\ \textgreater \ y =x+3} \atop {3^x*4^y = 768}} \right. \\ 3^x*4^{x+3} = 768 \\ 3^x*4^3*4^x = 768 \\ 3^x*4^x = 12 \\ (3*4)^x = 12 \\ x = 1 \\ y = 3 + 1 = 4 [/latex]