Докажите тождество, пожалуйста.

1)(a+5)/(5a-1)+(a+5)/(a+1)=(a+5)(a+1+5a-1)/(5a-1)(a+1)=6a(a+5)/(5a-1)(a+1) 2)6a(a+5)/(5a-1)(a+1) * (1-5a)/a(a+5)=-6/(a+1) 3)-6/(a+1)+(a²+5)/(a+1)=(-6+a²+5)/(a+1)=(a²-1)/(a+1)=(a-1)(a+1)/(a+1)=a-1