Log2x-log4x=3 с одз

[latex]\log_{2}x-\log_{4}x=3, \\ x\ \textgreater \ 0, \\ \log_{2}x-\log_{2^2}x=3\log_{2}2, \\ \log_{2}x-\frac{1}{2}\log_{2}x=\log_{2}2^3, \\ \log_{2}x-\log_{2}x^{\frac{1}{2}}=\log_{2}8, \\ \log_{2}\frac{x}{x^{\frac{1}{2}}}=\log_{2}8, \\ \log_{2}x^{\frac{1}{2}}=\log_{2}8, \\ x^{\frac{1}{2}}=8, \\ x=8^2, \\ x=64.[/latex]