Ответ(ы) на вопрос:
а) [latex]f(x)=-16x-2\\f(x)\ \textgreater \ 0=\ \textgreater \ -16x-2\ \textgreater \ 0=\ \textgreater \ x\ \textless \ -\frac{1}{8} [/latex]
б) [latex]f'(x)=x^{2}-2x\\f'(x)\ \textgreater \ 0=\ \textgreater \ x(x-2)\ \textgreater \ 0=\ \textgreater \ \left \[[ {{x\ \textgreater \ 2} \atop {x\ \textless \ 0}} \right. [/latex]
в) [latex]f'(x)=1-12x\\f'(x)\ \textgreater \ 0=\ \textgreater \ 1-12x\ \textgreater \ 0=\ \textgreater \ x\ \textless \ \frac{1}{12} [/latex]
г) [latex]f'(x)=-x^2-x\\f'(x)\ \textgreater \ 0=\ \textgreater \ -x(x+1)\ \textgreater \ 0=\ \textgreater \ -1\ \textless \ x\ \textless \ 0[/latex]
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