Определите, при каком значение а верно равенство

[latex] 1)\quad \frac{148:(8a-3)+6}{10} = \frac{2003}{2003} \\\\148:(8a-3)+6=1\cdot 10\\\\\frac{148}{(8a-3)}=4\\\\(8a-3)=\frac{148}{4}\\\\8a-3=37\\\\8a=40\\\\a=5[/latex] [latex]2)\quad \frac{7-102:(9a+7)}{4} = \frac{7}{7} \\\\7-102:(9a+7)=1\cdot 4\\\\102:(9a+7)=7-4\\\\\frac{102}{9a+7}=3\\\\9a+7=\frac{102}{3}\\\\9a+7=34\\\\9a=27\\\\a=3[/latex]