Помогите решить логарифмы 1 уравнение 2 неравенства

Уравнения: [latex]\displaystyle (\frac{1}{3})^{4-2x}=9\\\\3^{2x-4}=3^2\\2x-4=2\\x=3;\\\\\\5^{x+2}+5^x=130\\25\cdot5^x+5^x=130\\26\cdot5^x=130\\5^x=5\\x=1;\\\\\\3^{2x+1}-28\cdot3^x+9=0\\3\cdot3^{2x}-28\cdot3^x+9=0\;\big|\;3^x=t\\3t^2-28t+9=0\\\\\frac{D}{4}:(\frac{28}{2})^2-9*3=169=13^2\\\\t_1,_2=\frac{14\pm13}{3}; \quad t_1=9, \quad t_2=\frac{1}{3};\\\\3^x=9 \qquad \quad 3^2=\frac{1}{3}\\3^x=3^2\quad \; \; \quad 3^x=3^{-1}\\x=2; \qquad \quad x=-1.[/latex] Неравенства: [latex]\displaystyle 0,8^{2x-x^2} \geq 1\\\\(\frac{4}{5})^{2x-x^2} \geq (\frac{4}{5})^0\\\\2x-x^2 \leq 0\;\big|\;*(-1)\\x(x-2) \geq 0\\\\x_1=0; \qquad x_2=2;\\\\+++0---2+++\\\\x\in(-\ifty;0] \cup [2; +\infty);\\\\\\2^x\cdot3^x\ \textgreater \ 6^{2x^2}\cdot \frac{1}{6}\\6^x\ \textgreater \ 6^{-1}\cdot 6^{2x^2}\\6^x\ \textgreater \ 6^{2x^2-1}\\x\ \textgreater \ 2x^2-1\\2x^2-x-1\ \textless \ 0\\D:1+8=9=3^2\\\\x_1,_2=\frac{1\pm3}{4}; \qquad x_1=1, \qquad x_2=-\frac{1}{2};\\\\+++(-\frac{1}{2})---1+++ \\\\x\in (-\frac{1}{2};1);[/latex] [latex]\displaystyle 7^{x^2+4x} \geq (2^x)^{x+4}\\7^{x^2+4x} \geq 2^{x^2+4x}\;\big|\;:2^{x^2+4x}\\\\(\frac{7}{2})^{x^2+4x}=1\\\\(\frac{7}{2})^{x^2+4x}=(\frac{7}{2})^0\\\\x^2+4x \geq 0\\x(x+4) \geq 0\\\\x_1=0; \qquad x_2=-4;\\\\+++(-4)---0+++\\\\x\in(-\infty;-4)\cup [0;+\infty).[/latex]