Решите систему уравнений. {2х-3(2у+1)=15 3(х+1)+3у=2у-2

[latex] \left \{ {{2x-3(2y+1)=15} \atop {3(x+1)+3y=2y-2}} \right. \\ \\ \left \{ {{2x-6y-3=15} \atop {3x+3+3y=2y-2}} \right. \\ \\ \left \{ {{2x-6y=18} \atop {3x+3y-2y=-2-3}} \right. \\ \\ \left \{ {{x-3y=9} \atop {3x+y=-5}} \right. \\ \\ \left \{ {{x-3(-3x-5)=9} \atop {y=-3x-5}} \right. \\ \\ \left \{ {{10x=-6} \atop {y=-3x-5}} \right. \\ \\ \left \{ {{x=-0,6} \atop {y=-3,2}} \right. [/latex] Ответ: {-0,6; -3,2}