Решите уравнение 1) (1,8-0,3у)(2у+9)=0 2)(5у+4)(1,1у-3,3)=0 Помогите плиз

1) (1.8-0.3y)(2y+9)=0 3.6y+16.2-0.6y²-2.7y=0 -0.6y²+0.9y+16.2=0 -6y²+9y+162=0 -2y²+3y+54=0 D=9-4*(-2)*54=441 x1=(-3+21)/(-4)=-4.5 x2=(-3-21)/(-4)=6 2) (5y+4)(1.1y-3.3)=0 5.5y²-16.5y+4.4y-13.2=0 5.5y²-12.1y-13.2=0 55y²-121y-132=0 5y²-11y-12=0 D=121-4*5*(-12)=361 x1=(11+19)/10=3 x2=(11-19)/10=-8/10=-4/5=-0.8