(x-3) (x²+3x+9)=x(x-8) (x+9)?????????????????

[latex](x-3) (x^2+3x+9)=x(x-8) (x+9) \\ \\ x^3 -27 = (x^2-8x)(x+9) \\ \\ x^3 -27 = x^3 + 9x^2 -8x^2 -72x \\ \\ x^2 -72x +27 = 0 \\ \\ D = (-72)^2 - 4 * 1 * 27 = 5184-108 = 5076 \\ \\ x1 = \frac{72 + 6 \sqrt{141} }{2} = 36+3 \sqrt{141} \\ \\ x2 = \frac{72 - 6 \sqrt{141} }{2} = 36-3 \sqrt{141} [/latex]