Курсовая работа: Динамическое формирование и преобразование списков и структур

printf("\n Time: %s", p->pro[n].time);

printf("\n");

}

printf("\n\nAny key to next record...");

getch();

p=p->next;

}

return start;

}

///////////////////////////PRINT NEW LIST ON SCREEN//////////////////////////

void *printnew (mg *start2) {

int n;

mg *p2=start2;

clrscr();

while(p2!=NULL) {

clrscr();

printf("\nMAGAZINE #%d", p2->num);

printf("\n Address");

printf("\n City: %s", p2->adr.city);

printf("\n Street: %s", p2->adr.str);

printf("\n House: %d", p2->adr.dom);

printf("\nProducts");

for(n=0;n<5;n++) {

printf("\n %d)", n+1);

rintf("\n Name: %s", p2->pro[n].name);

printf("\n Price: %d", p2->pro[n].price);

printf("\n Time: %s", p2->pro[n].time);

printf("\n");

}