Курсовая работа: Электродинамический преобразователь энергии с тиристорной схемой питания

LOCATE 1, 1: PRINT "t="; tall * 1000, " "

LOCATE 2, 1: PRINT "I="; I, " "

LOCATE 3, 1: PRINT "Uб="; Uc, " "

LOCATE 4, 1: PRINT "X="; X * 1000, " "

LOCATE 5, 1: PRINT "V="; V * 1000, " "

LOCATE 6, 1: PRINT "a="; a, " "

LOCATE 7, 1: PRINT "Ua="; Ua, " "

END IF

PSET (t * 20000 * .01 / t2, 250 - I * .5)

PSET (t * 20000 * .01 / t2, 250 + Uc * .1), 3

PSET (t * 20000 * .01 / t2, 250)

PSET (t * 20000 * .01 / t2, 250 - V * 100), 4

PSET (t * 20000 * .01 / t2, 250 - X * 100000), 5

PSET (t * 20000 * .01 / t2, 250 - a / 3), 2

PSET (t * 20000 * .01 / t2, 250 - Ua * .1), 6

LET t = t + h

IF t > ti + t1 + t56 THEN GOTO 27

GOTO 20

27i5 = I

V5 = V

x5 = X

28LET k1i = -E / La - (R / La) * i5 - (Bo * Pi * D * w * V / La)

LET i5 = I + h * .5 * k1i

LET k2i = -E / La - (R / La) * i5 - (Bo * Pi * D * w * V / La)

LET i5 = I + k2i * h * .5

LET k3i = -E / La - (R / La) * i5 - (Bo * Pi * D * w * V / La)

LET i5 = I + k3i * h

LET k4i = -E / La - (R / La) * i5 - (Bo * Pi * D * w * V / La)

LET di = h * (2 * k2i + k1i + 2 * k3i + k4i) / 6