Курсовая работа: Редуктор коническо-цилиндрический

R_bg =(F_t2 *l₁ + F_t1 (l₁ +l₂ ))/(l₁ +l₂ +l₃ ) = 2333.8

å M_B =0;

R_ag (l₁ +l₂ +l₃ ) +F_t1 *l₃ +F_t2 (l₂ +l₃ ) =0;

R_ag = (-F_t1 *l₃ – F_t2 (l₂ +l₃ ))/(l₁ +l₂ +l₃ ) = -1928.79

Проверка найденных сил:

å X = -1928.79–2333.8 +3258.69+1003.92 = 0

Реакции опор в плоскости ZOY:

å M_A =0;

– F_a2 *d₁ /2+F_r2 *l₁ -F_r1 *(l₁ +l₂ ) – F_a1 *d₂ /2 – R_bb *(l₁ +l₂ +l₃ ) =0;

R_bb =(-F_a2 *d₁ /2+F_r2 *l₁ -F_r1 *(l₁ +l₂ ) – F_a1 *d₂ /2)/(l₁ +l₂ +l₃ ) = -977.96

å M_B =0;

– F_a2 *d₁ /2 – F_r2 *(l₂ +l₃ )+F_r1 *l₃ – F_a1 *d₂ /2 – R_ab *(l₁ +l₂ +l₃ )=0;

R_ab = (-F_a2 *d₁ /2 – F_r2 *(l₂ +l₃ )+F_r1 *l₃ – F_a1 *d₂ /2)/(l₁ +l₂ +l₃ ) = 141.99

Проверка найденных сил:

å X = 141.99 +977.96+96.5–1216.48 = 0

R_rB = =2530.38;

R_rA = = 1934

Построение эпюр моментов:

В плоскрсти ZOY

Сечение А: M_x – R_ab x = 0

M_x = R_ab x

x=0 -> M_x =0; x =l₁ = 42.5 -> M_x = 6.03

Сечение E: M_x – R_ab (l₁ +x) – F_{a 2} d₁ /2 – F_{r 2} x =0

M_x = R_ab (l₁ +x) + F_a2 d₁ /2 + F_r2 x =0

M_x = x(R_ab + F_r2 ) +R_ab l₁ + F_a2 d₁ /2

x = 0 -> M_x = 29.99; x = l₂ = 60.5 ->M_x = 44.41

Сечение B: M_x – R_ab (l₁ +l₂ +x) – F_r2 (l₂ +x) – F_a2 d₁ /2 – F_a1 d₂ /2 +F_r1 x = 0

M_x = R_ab (l₁ +l₂ +x)+F_r2 (l₂ +x) + F_a2 d₁ /2 +F_a1 d₂ /2 – F_r1 x