1.) a^2-3a+2/a^2-5a+6 ; 2.) a^2+5a+6/a^2+6a+9 ; 3.) 5a^2-9a-2/a^2-3a+2 ; 4.) m^3-m^2+m-1/m^2+1 ; 5.) 6x^2+x-2/3x^2-4x-4; 6.) 10x^2+x-2/x^2+2,1x-1; Упростить помогите решить задание 8 кл

1) [latex] \frac{a^2-3a+2}{a^2-5a+6} = \frac{(a-1)(a-2)}{(a-2)(a-3)} = \frac{a-1}{a-3} [/latex] 2) [latex] \frac{a^2+5a+6}{a^2+6a+9} = \frac{(a+2)(a+3)}{(a+3)(a+3)} = \frac{a+2}{a+3} [/latex] 3) [latex] \frac{5a^2-9a-2}{a^2-3a+2} = \frac{(5a+1)(a-2)}{(a-1)(a-2)} = \frac{5a+1}{a-1} [/latex] 4) [latex] \frac{m^3-m^2+m-1}{m^2+1} = \frac{(m-1)(m^2+1)}{m^2+1} = m-1 [/latex] 5) [latex] \frac{6x^2+x-2}{3x^2-4x-4} = \frac{(2x-1)(3x+2)}{(3x+2)(x-2)} = \frac{2x-1}{x-2} [/latex] 6) [latex] \frac{10x^2+x-2}{x^2+2,1x-1} = \frac{(5x-2)(2x+1)}{(x-0,4)(x+2,5)} = \frac{5(x-0,4)(2x+1)}{(x-0,4)(x+2,5)} = \frac{5(2x+1)}{(x+2,5)} = \frac{(10x+5)}{(x+2,5)}[/latex]  Удачи!