1) sina+sin2a+sin3a+sin4a=?2) cos2a-cos4a-cos6a+cos8a=?3) cosa=1/ [latex] \sqrt{3} [/latex]cos2a-cos6a=?4) sina=2/ [latex] \sqrt{5} [/latex]sin5a-sin3a=?
1) sina+sin2a+sin3a+sin4a=?
2) cos2a-cos4a-cos6a+cos8a=?
3) cosa=1/ [latex] \sqrt{3} [/latex]
cos2a-cos6a=?
4) sina=2/ [latex] \sqrt{5} [/latex]
sin5a-sin3a=?
Ответ(ы) на вопрос:
[latex](sina+sin4a)+(sin2a+sin3a) = 2sin\frac{5a}{2}*cos\frac{3a}{2}+2sin\frac{5a}{2}*cos\frac{a}{2}\\ 2sin\frac{5a}{2}(cos\frac{3a}{2}+cos\frac{a}{2})[/latex]
[latex](cos2a+cos8a)-(cos4a+cos6a)=\\ 2cos5a*cos3a-(2cos5a*cosa)=2cos5a(cos3a-cosa)[/latex]
[latex]cosa=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}\\ sina=\frac{\sqrt{6}}{{3}}\\ cos2a-cos6a=16sina*cosa*(2cos^2a-1)*sina*cosa=\\ 16*\frac{\sqrt{18}}{3}*(2*\frac{1}{3}-1)*\frac{\sqrt{18}}{3}= -\frac{32}{3} [/latex]
[latex]sina=\frac{2}{\sqrt{5}}\\ sin5a-sin3a=\\ 2sina*(2(1-2sin^2a)^2-1)=\frac{4}{\sqrt{5}}(2* \frac{9}{25} -1) = \frac{4}{\sqrt{5}}*-\frac{7}{25}=\\ -\frac{28}{25\sqrt{5}}[/latex]
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