1) (x+10)^2+(x+6)^2=2x^2 2) -2х^2+3x-4=-x^2-x+(2-x^2) 3) -4x^2-4x=0

Question

1) (x+10)^2+(x+6)^2=2x^2 2) -2х^2+3x-4=-x^2-x+(2-x^2) 3) -4x^2-4x=0

Алгебра

1) (x+10)^2+(x+6)^2=2x^2 2) -2х^2+3x-4=-x^2-x+(2-x^2) 3) -4x^2-4x=0

Гость

Ответ(ы) на вопрос:

Accepted Answer

1) x^2 + 20x + 100 + x^2 + 12x + 36 = 2x^2 2x^2 - 2x^2 + 32x = - 136 32x = - 136 x= - 4,25 2) - 2x^2 + 3x - 4 + x^2 + x - 2 + x^2 =0 - 2x^2 + 2x^2 + 4x - 6 =0 4x = 6 x= 1,5 3) - 4x^2 - 4x = 0 x^2 + x = 0 x( x + 1) = 0 x = 0 x + 1 =0 x = - 1