4 целых 5/14+(5 целых 1/12-3 целых 4/21) помогите пожалкйста"

4[latex] \frac{5}{14} [/latex] + (5[latex] \frac{1}{142 [/latex] - 3[latex] \frac{4}{21} [/latex]) = 4[latex] \frac{5}{14} [/latex] + ([latex] \frac{61}{12} [/latex] - [latex] \frac{67}{21} [/latex]) = [latex] \frac{61}{14} [/latex] - [latex] \frac{3}{21} [/latex] = [latex] \frac{177}{42} [/latex] = 4[latex] \frac{9}{42} [/latex]