(44а²вс³)(2ас)(3ав³)/6а²в³с= (m-n)^2+(m+n)²/2m=

Question

(44а²вс³)(2ас)(3ав³)/6а²в³с= (m-n)^2+(m+n)²/2m=

Алгебра

(44а²вс³)*(2ас)*(3ав³)/6а²в³с= (m-n)^2+(m+n)²/2m=

Гость

Ответ(ы) на вопрос:

Accepted Answer

[latex] \frac{44a^2bc^3\cdot 2ac\cdot 3ab^3}{6a^2b^3c} = \frac{44\, a^4b^4c^4}{a^2b^3c} =44\, a^2bc^3\\\\ \frac{(m-n)^2+(m+n)^2}{2m} = \frac{m^2-2mn+n^2+m^2+2mn+n^2}{2m} = \frac{2(m^2+n^2)}{2m} = \frac{m^2+n^2}{m} [/latex]