5x^2-10xy+5y^2 8x-8y --------------------- : ----------------- 2x^2-2xy+2y^2 10x^3+10y^3
5x^2-10xy+5y^2 8x-8y --------------------- : ----------------- 2x^2-2xy+2y^2 10x^3+10y^3
Гость
Ответ(ы) на вопрос:
Гость[latex] \frac{5(x^{2}-2xy+y^{2})}{2(x^{2}-xy+y^{2})}: \frac{8(x-y)}{10(x+y)(x^{2}-xy+y^{2})}=\frac{5(x-y)^{2}}{2(x^{2}-xy+y^{2})}* \frac{10(x+y)(x^{2}-xy+y^{2})}{8(x-y)}= \\ = \frac{25(x-y)(x+y)}{8}=\frac{25(x^{2}-y^{2})}{8} [/latex]
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