Cos(x/2-pi/12)(sin(x-pi/3)+1)=0

1) cos(x/2-π/12)=0 x/2-π/12=π/2 + πk, k∈Z x/2=π/12  + π/2 + πk x/2= π/12 + 6π/12 + πk x/2 = 7π/12 + πk x= 2(7π/12 + πk) x=7π/6 + 2πk, k∈Z 2) sin(x-π/3)+1=0 sin(x-π/3)= -1 x-π/3= -π/2 + 2πn, n∈Z x=π/3 - π/2 + 2πn x=2π/6 - 3π/6 + 2πn x= - π/6 + 2πn, n∈Z Ответ: 7π/6 + 2πk, k∈Z;             - π/6 + 2πn, n∈Z