Даю 25 БАЛЛОВ. Помогите решить неравенство [latex] \sqrt{5-x^{2} } \ \textgreater \ x-1[/latex]

[latex] \sqrt{5-x^2} \ \textgreater \ x -1 \\ ( \sqrt{5-x^2})^2 \ \textgreater \ (x -1)^2 \\ 5-x^2\ \textgreater \ x^2-2x+1 \\ 5-x^2-x^2+2x-1\ \textgreater \ 0 \\ 4-2x^2+2x\ \textgreater \ 0 \\ -2x^2+2x+4\ \textgreater \ 0 \\ x^2-x-2 \ \textgreater \ 0 \\ x_1=2; \\ x_2=-1;[/latex]