Добрый вечер решите не равенство

[latex]x-7+ \frac{(x-6)^2}{3} \geq \frac{(x+4)^2}{2} - \frac{(x+2)(x+6)}{4} [/latex] [latex]\frac{3(x-7)+(x-6)^2}{3} \geq \frac{2(x+4)^2}{4} - \frac{(x+2)(x+6)}{4} [/latex] [latex]\frac{3x-21+x^2-12x+36}{3} \geq \frac{2(x^2+8x+16)}{4} - \frac{ x^{2} +2x+6x+12}{4} [/latex] [latex]\frac{x^2-9x+15}{3} \geq \frac{2x^2+16x+32-x^2-8x-12}{4} [/latex] [latex]\frac{x^2-9x+15}{3} \geq \frac{x^2+8x+20}{4} [/latex] [latex]4(x^2-9x+15) \geq {3(x^2+8x+20)[/latex] [latex]4x^2-36x+60 \geq {3x^2+24x+60[/latex] [latex]4x^2-36x+60 -{3x^2-24x-60 \geq 0[/latex] [latex]x^2-60x \geq 0[/latex] [latex]x(x-60) \geq 0[/latex] [latex]x=0[/latex]    [latex]x=60[/latex] -----+------[0]---------_--------[60]------+------- ///////////////                               ////////////////// Ответ: [latex](-[/latex] ∞ [latex];0][/latex] ∪ [latex][60;+[/latex] ∞ [latex])[/latex]