F(x)=sin(2-3x)y=e^cos^2 x

а)  f(x)=sin(2-3x) f ' (x)= -3cos(2-3x) б) y=e^(cos²x) y ' = e^(cos²x) * 2cosx*(-sinx)= -e^(cos²x)*sin2x=-sin2x*e^(cos²x) 4) ∛1,06 =(1+0,06)^(¹/₃) f(x₀+Δx)≈f(x₀)+ f '(x₀)*Δx x₀=1             Δx=0.06 f(x₀)=1^(¹/₃)=1 f '(x)=1/(3 ³√x²) f '(1)=1/3 ∛(1.06)=1+ ¹/₃ * 0.06=1+0.02=1.02 5. y=cos(5x) y ' = (cos(5x))' * (5x)' = -5sin5x y '' = (-5sin5x)' = -5(sin(5x))' * (5x)' = -25cos5x