F(x)=x^3-3x, x є [0,2]

F`(x)=3x²-3=0 3(x-1)(x+1)=0 x=1∈[0;2] x=-1∉[0;2] F(0)=0 f(1)=1-3=-2наим F(2)=8-6=2наиб