Как правильно решить 37/48:5 2/7 - 19/42 *7/8+ 4 1/5

[latex] \frac{37}{48} :5 \frac{2}{7} - \frac{19}{42} * \frac{7}{8} +4 \frac{1}{5}=3 \frac{19}{20} \\ 1) \frac{37}{48} :5 \frac{2}{7}= \frac{37}{48} * \frac{7}{37}= \frac{7}{48} \\ 2)\frac{19}{42} * \frac{7}{8}= \frac{19*1}{6*8} = \frac{19}{48} \\ 3) \frac{7}{48} -\frac{19}{48}=-\frac{12}{48}=- \frac{1}{4} \\ 4)- \frac{1}{4}+4 \frac{1}{5} =3 \frac{24}{20} - \frac{5}{20} =3 \frac{19}{20} \\ [/latex]

37/48:5 2/7 - 19/42 *7/8+ 4 1/5=3 19/20  1)37/48:5 2/7=37/48*7/37=7/48 2) - 19/42 *7/8=-19/48 3)4 1/5+7/48-19/48=4  1/5-1/4= 3 6/5-1/4=3 24/20-5/20= 3 19/20