(х^2-1)^2+(x-1)^4=0 помогите решить уравнение :)

[latex](x^2-1)+(x-1)^4=0\\\\(x-1)(x+1)+(x-1)^4=0\\\\(x-1)(x+1+(x-1)^3)=0\\\\(x-1)(x^3-3x^2+4x)=0\\\\(x-1)\cdot x\cdot (x^2-3x+4)=0\\\\x_1=0\; ,\; \; x_2=1\\\\x^2-3x+4=0\; ,\; D=9-16\ \textless \ 0\; \to \; \; x^2-3x+4\ \textgreater \ 0\; pri\; x\in R\\\\Otvet:\; x_1=0,\; x_2=1.[/latex]