Х^2-5х-3=2х-5манинде тен болады

[latex] x^{2} -5x-3=2x-5[/latex] [latex] x^{2} -5x-2x-3+5=0[/latex] [latex] x^{2} -7x+2=0[/latex] [latex]D= b^{2} -4ac=(-7)^2-4*2*1=49-8=41[/latex] [latex] x_{1} ; x_{2}= \frac{-b+- \sqrt{D} }{2a} = \frac{7+- \sqrt{41} }{2} [/latex] Ответ: [latex] x= \frac{7+- \sqrt{41} }{2} [/latex]