Корень из {x+3y+8}=2 корень из (2х-у+2)=1 это система

[latex] \sqrt{x+3y+8}=2[/latex] [latex] \sqrt{2x-y+2} =1[/latex] [latex]x+3y+8=4[/latex] [latex]2x-y+2=1[/latex] [latex]x+3y=-4[/latex] [latex]2x-y=-1[/latex] [latex]x+3y=-4[/latex] [latex]6x-3y=-3[/latex] [latex]7x=-7[/latex] [latex]x+3y=-4[/latex] [latex]x=-1[/latex] [latex]y=2x+1[/latex] [latex]x=-1[/latex] [latex]y=-1[/latex] Ответ: (-1; -1)

ОДЗ [latex]x+3y+8 \geq 0 \\ x+3y \geq -8 \\ \\ 2x-y +2 \geq 0 \\ 2x-y \geq -2 \\ [/latex] [latex] \left \{ { \sqrt{x+3y+8}=2 } \atop { \sqrt{2x-y+2} =1}} \right. \\ \\ \left \{ {x+3y+8=4} \atop {2x-y+2=1}} \right. \\ \\ \left \{ {{x+3y+4=0} \atop {2x-y+1=0}} \right. \\ \\ \left \{ {{x+3y+4=0} \atop {6x-3y+3=0}} \right. \\ \\ \left \{ {{7x+7=0} \atop {x+3y+4=0}} \right. \\ \\ \left \{ {{x=-1} \atop {-1+3y+4=0}} \right. \\ \\ \left \{ {{y=-1} \atop {x=-1}} \right. [/latex] x=-1 y=-1 подходят по ОДЗ Ответ: -1;-1