[latex] \frac{ a^{2}-4 b^{2} }{2ab} : ( \frac{1}{2b} - \frac{1}{a} ) [/latex] при a=[latex]5 \frac{11}{17} [/latex] и [latex]7 \frac{3}{17} [/latex]

Question

[latex] \frac{ a^{2}-4 b^{2} }{2ab} : ( \frac{1}{2b} - \frac{1}{a} ) [/latex] при a=[latex]5 \frac{11}{17} [/latex] и [latex]7 \frac{3}{17} [/latex]

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Ответ(ы) на вопрос:

Accepted Answer

[latex] \frac{a^{2}-4b^{2}}{2ab}:( \frac{1}{2b}- \frac{1}{a})= \frac{a^{2}-4b^{2}}{2ab}: \frac{a-2b}{2ab}= \frac{(a-2b)(a+2b)*2ab}{2ab*(a-2b)}=a+2b \\ 5 \frac{11}{17}+2*7 \frac{3}{17}= \frac{96}{17}+ \frac{244}{17}= \frac{340}{17}=20 [/latex]