[latex] \frac{c^{9}-1 }{5c^{2}+5c+5 }: \frac{4c^{6}+4c^{3} +4 }{10c+10} [/latex] при=-3

[latex] \frac{c^{9}-1 }{5c^{2}+5c+5 }: \frac{4c^{6}+4c^{3} +4 }{10c+10}= \frac{(c ^{3}-1)(c^{6}+c ^{3}+1)}{5(c ^{2}+c+1) }* \frac{10(c+1)}{4(c ^{6}+c^{3}+1)}= \\ \frac{(c-1)(c ^{2}+c+1)}{5(c ^{2}+c+1) }* \frac{10(c+1)}{4}= \frac{(c-1)(c+1)}{2}=0.5(c-1)(c+1)=0.5(c ^{2}-1) [/latex] 0.5((-3)²-1)=0.5(9-1)=0.5*8=4