[latex]( \frac{x-1}{x} )^{2} +( \frac{x-1}{x-2} )^{2}= \frac{40}{9}[/latex]
[latex]( \frac{x-1}{x} )^{2} +( \frac{x-1}{x-2} )^{2}= \frac{40}{9}[/latex]
Ответ(ы) на вопрос:
[latex] \frac{ (x-1)^{2} }{ x^{2} } + \frac{(x-1)^{2}}{(x-2)^{2}} = \frac{40}{9} [/latex]
[latex] \frac{(x-1)^{2}(x-2)^{2} + x^{2} (x-1)^{2}}{ x^{2} (x-2)^{2}} = \frac{40}{9} [/latex]
[latex] \frac{(2x^{2}-4x+4)( x^{2}-2x+1)}{ x^{2}(x-2)^{2} } = \frac{40}{9} [/latex]
[latex] \frac{2(x^{2}-2x+2)( x^{2}-2x+1)}{ (x^{2}-2x)^{2} } = \frac{40}{9} [/latex]
Замена x^2 - 2x = y. И делим все на 2
[latex] \frac{(y+2)(y+1)}{ y^{2}} = \frac{20}{9} [/latex]
[latex]9( y^{2}+3y+2) = 20 y^{2} [/latex]
[latex]11 y^{2} -27y-18=0[/latex]
[latex](y-3)(11y+6)=0[/latex]
[latex]y1 = x^{2} -2x=3; (x+1)(x-3)=0[/latex]
x1 = -1;x2 = 3
[latex]y2= x^{2} -2x=-6/11; 11 x^{2} -22x+6=0[/latex]
[latex]D/4= 11^{2} -11*6=121-66=55[/latex]
[latex]x3=(11- \sqrt{55} )/11 = 1- \sqrt{ \frac{5}{11} } [/latex]
[latex]x3=(11+ \sqrt{55} )/11 = 1+ \sqrt{ \frac{5}{11} } [/latex]
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