[latex] log_{5}x+ log_{5}31= log_{5}93- log_{5}4 [/latex]

ОДЗ:   [latex]x\ \textgreater \ 0[/latex] Решение: [latex]log_{5}x+ log_{5}31= log_{5}93- log_{5}4 \\ \\ log_{5}x= log_{5}93- log_{5}4 -log_{5}31 \\ \\ log_5x=log_5 \frac{93}{4*31} \\ \\ log_5x=log_5{ \frac{93}{124} } \\ \\ log_5x=log_50,75 \\ x=0,75[/latex] Ответ:  [latex]0,75[/latex]