[latex](x^{2}+2x)^{2}-2(x+2)(x^{2}-x)-15(x^{2}-2x+1)=0[/latex]Найдите корни уравнения

[latex](x^2+2x)^2-2(x+2)(x^2-x)-15(x^2-2x+1)=0, \\ (x(x+2))^2-2x(x+2)(x-1)-15(x-1)^2=0, \\ ((x(x+2))^2-2x(x+2)(x-1)+(x-1)^2)-16(x-1)^2=0, \\ (x(x+2)-(x-1))^2=16(x-1)^2, \\ (x^2+x+1)^2=(4x-4)^2, \\ \left \[ {{x^2+x+1=4x-4,} \atop {x^2+x+1=-(4x-4);}} \right. \\ x^2-3x+5=0, \\ D=-11<0; \\ x^2+5x-3=0, \\ D=37, \\ x_1=-2,5-0,5\sqrt{37}, \\ x_2=-2,5+0,5\sqrt{37}.[/latex]