Ответ(ы) на вопрос:
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Logₓ₊₁ x²-x-2≤1
00
-10
x²-x-2-x-1≥0, x²-2x-3≥0
D=4+4·3=16, √D=4, x ₁=(2+4)/3=3, x₂=(2-4)/2=-1
(x-3)(x+1)≥0
+ - - +
---------------------- -1--------------------0---------------2------3------>x
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x∈∅
x>0
(x+1)(x-2)>0
x²-2x-3≤0 ,(x+1)(x-3)≤0
////////////////////////////// ////////////////////////////////////////////
--------------------- -1 -------------0---------------2--------------3------------------->x
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x∈(2;3]
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