Ответ(ы) на вопрос:
[latex]log_{0,3}(2x-4)\ \textgreater \ log_{0,3}(x+1)\\\\ \left \{ {{2x-4\ \textgreater \ 0} \atop {x+1\ \textgreater \ 0}} \right.\\\\ \left \{ {{2x\ \textgreater \ 4} \atop {x\ \textgreater \ -1}} \right.\\\\ \left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ -1}} \right.=\ \textgreater \ x\ \textgreater \ 2\\\\0\ \textless \ 0,3\ \textless \ 1\\\\2x-4\ \textless \ x+1\\2x-x\ \textless \ 1+4\\x\ \textless \ 5\\\\x\in(2;5) [/latex]
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