Log4(7-3x)=log4(5-x) 4 основание

[latex] log_{4} (7-3x)= log_{4}(5-x)[/latex] [latex]7-3x=5-x[/latex] [latex]-3x+x=-7+5[/latex] [latex]-2x=-2[/latex] [latex]x=1[/latex] ОДЗ: [latex] \left \{ {{7-3x\ \textgreater \ 0} \atop {5-x\ \textgreater \ 0}} \right. [/latex] [latex] \left \{ {{x\ \textless \ \frac{7}{3} } \atop {x\ \textless \ 5}} \right. [/latex] Значит ОДЗ: (-∞;7/3) Ответ: 1