Найдите корень уравнения.[latex] \sqrt{ \frac{8}{3x-43} } = \frac{1}{4} [/latex]

[latex] (\sqrt{\frac{8}{3x-43}})^{2} = (\frac {1}{4})^{2} \\ \frac{8}{3x-43} = \frac{1}{16} \\ 128 = 3x-43 \\ 128+43 = 3x - 43 +43 \\ 171 = 3x \\ x = \frac{171}{3} \\ x = 57[/latex]