Найдите корни уравнения 40+16х-2/х^2-5/х^3=0

40+16x-2/x²-5/x³=0  |×x³                        ОДЗ: х²≠0   х³≠0   х≠0 40x³+16x⁴-2x-5=0 16x⁴+40x³-2x-5=0 x₁=0,5 16x⁴+40x³-2x-5   |_x-0,5_ 16x⁴-8x³                | 16x³+48x²+22x+10 ------------             48x³-2x             48x³-24x²             ------------                      22x²-2x                      22x²-12x                      ------------                                10x-5                                10x-5                                 -------                                         0 16x³+48x²+22x+10=0 x₂=-2,5 16x³+48x²+22x+10  |_x+2,5_ 16x³+40x²                  | 16x²+8x+2 ------------               8x²+22x               8x²+20x              ------------                         2x+10                         2x+10                         --------                                   0 16x²+8x+2=0    |÷2 8x²+4x+1=0     D=-16  ⇒  Уравнение не имеет действительных корней. Ответ: х₁=0,5     х₂=-2,5.