Найдите область определения функций y=√(12-x^2-x)/√(x+3)

[latex]y= \frac{ \sqrt{12- x^{2} -x} }{ \sqrt{x+3} } [/latex] [latex] \left \{ {{- x^{2} -x+12 \geq 0} \atop {x+3\ \textgreater \ 0}} \right. [/latex] [latex] \left \{ {{ x^{2} +x-12 \leq 0} \atop {x\ \textgreater \ -3}} \right. [/latex] [latex]D=1+48=49[/latex] [latex]x_1=3[/latex] [latex]x_2=-4[/latex] [latex] \left \{ {{(x-3)(x+4) \leq 0} \atop {x\ \textgreater \ -3}} \right. [/latex] [latex]D(y)=(-3;3][/latex]