Найдите производную функции f (x)=sin (4-3x)tg (4-3x)

[latex]f'_x (x)=[sin (4-3x)tg (4-3x)]'_x=[/latex] [latex]=[sin(4-3x)]'_x*tg(4-3x)+sin(4-3x)*[tg(4-3x)]'_x=[/latex] [latex]=cos(4-3x)*[4-3x]'_x*tg(4-3x)+[/latex] [latex]+sin(4-3x)* \frac{1}{cos^2(4-3x)}*[4-3x]'_x =[/latex] [latex]=[cos(4-3x)*tg(4-3x)+ \frac{sin(4-3x)}{cos^2(4-3x)}]*[4-3x]'_x =[/latex] [latex]=[cos(4-3x)* \frac{sin(4-3x)}{cos(4-3x)} + \frac{sin(4-3x)}{cos^2(4-3x)}]*[0-3]=[/latex] [latex]=-3[sin(4-3x) + \frac{sin(4-3x)}{cos^2(4-3x)}] =-3sin(4-3x)[ 1+ \frac{1}{cos^2(4-3x)}][/latex]