Найти обратную функцию: f(x)= 5 - ( 1/x ) f(x)= (x+1)/(x-2)

[latex]1)\quad y=5-\frac{1}{x}\\\\\frac{1}{x}=5-y\\\\x=\frac{1}{5-y}\; \; \to \; \; \boxed {y=\frac{1}{5-x}}\; \; -\; \; obratnaya\; fynkciya\\\\\\2)\quad y= \frac{x+1}{x-2} \\\\y(x+1)=x-2\\\\xy-x=-y-2\\\\x(y-1)=-(y+2)\\\\x=-\frac{y+2}{y-1} \; \; \; \to \; \; \boxed {y=-\frac{x+2}{x-1}}\; \; -\; \; obratnaya\; fynkciya[/latex]