Найти производную [latex] \frac{4}{ \sqrt[3]{ x^{2} } } + \frac{x+1}{ \sqrt{x} } [/latex]

[latex]y= \frac{4}{\sqrt[3] {x^2}} +\frac{x+1}{\sqrt{x}}\\\\y=4\cdot x^{-\frac{2}{3}}+(x+1)\cdot x^{-\frac{1}{2}}}=4\cdot x^{-\frac{2}{3}}+x^{\frac{1}{2}}+x^{-\frac{1}{2}}\\\\y'=-4\cdot \frac{2}{3}x^{-\frac{5}{3}}+\frac{1}{2}\cdot x^{-\frac{1}{2}}-\frac{1}{2}\cdot x^{-\frac{3}{2}}=- \frac{8}{3\sqrt[3]{x^5}} +\frac{1}{2\sqrt{x}}-\frac{1}{2\sqrt{x^3}}[/latex]