Очень срочно !! Алгебра 7 класс, ответ отмечу как лучший )

а) [latex] \frac{3^{12}*(3^4)^5}{(3^{15})^2} = \frac{3^{12}*3^{20}}{3^{30}}=[/latex][latex]= \frac{3^{32}}{3^{30}}=3^{2}=9[/latex] б) [latex] \frac{25^4*5}{125^3} = \frac{(5^2)^4*5}{(5^3)^3}= \frac{5^8*5}{5^9}= \frac{5^9}{5^9} =1 [/latex] в) [latex] \frac{128^5}{32^4*64^2} = \frac{(2^7)^5}{(2^5)^4*(2^6)^2} = \frac{2^{35}}{2^{20}*2^{12}} = \frac{2^{35}}{2^{32}}=2^3=8 [/latex] г) [latex] \frac{6^{12}}{(2^5*3^7)^2} = \frac{2^{12}*3^{12}}{2^{10}*3^{14}}= \frac{2^2}{3^2} = \frac{4}{9} [/latex] д) [latex] \frac{21^8}{9^7*7^9}= \frac{3^8*7^8}{3^{14}*7^9} = \frac{1}{3^6*7} = \frac{1}{5103} [/latex] е) [latex] \frac{125^3*81^2}{15^{10}}= \frac{(5^3)^3*(3^4)^2}{5^{10}*3^{10}}= \frac{5^9*3^{8}}{5^{10}*3^{10}}= \frac{1}{5*3^2}= \frac{1}{45} [/latex] ж) [latex]0.125^{12}*2^{37}=( \frac{1}{8})^{12}*2^{37} =2^{-36}*2^{37}=2[/latex] з) [latex]( \frac{1}{3} )^{17}*81^4=3^{-17}*(3^4)^4=3^{-17}*3^{16}=3^{-1}= \frac{1}{3} [/latex] и) [latex]( \frac{3}{5} )^{27}*( \frac{125}{27})^8 =( \frac{3}{5} )^{27}*(( \frac{5}{3})^3)^8=( \frac{3}{5} )^{27}*(\frac{5}{3})^{24}=( \frac{3}{5} )^{27}*(\frac{3}{5})^{-24}=( \frac{3}{5} )^{3}=[/latex][latex]= \frac{27}{125} [/latex]