Плес решите)Только номер 1

[latex]1)\; \; 4(3x-4)-3(4x-3) \leq 1-5x\\\\12x-16-12x+9 \leq 1-5x\\\\-7 \leq 1-5x\\\\5x \leq 8\\\\x \leq 1,6\\\\2)\; \; \frac{11x-4}{5} \geq \frac{x^2}{2} \; |\cdot 10\\\\ 2(11x-4) \geq 5x^2\\\\22x-8 \geq 5x^2\\\\5x^2-22x+8 \leq 0\\\\D/4=81\; ,\; \; x_1= \frac{11-9}{5} = \frac{2}{5}=0,4\; ;\; \; x_2= \frac{11+9}{5} =4\\\\5(x-0,4)(x-4) \leq 0\qquad +++[\, 0,4\, ]---[\, 4\, ]+++\\\\x\in [\, 0,4\, ;\, 4\, ][/latex]